Not all functions are (Riemann) integrable!

1. After thinking for a moment, I should probably mention that not every function is (Riemann) integrable. Conversely, just because we throw something into an integral expression \int\dots\,\mathrm{d}x doesn’t make it a function.

2. Consider the function
(1)\displaystyle\chi_{\mathbb{Q}}(x) = \begin{cases}1 & x\mbox{ is rational}\\  0 & \mbox{otherwise}\end{cases}
What is its integral on the domain [0,1]? Well, using the Riemann sum, this depends on the partition. We can pick a partition whose end points are all rational; conversely we can pick one whose endpoints (except at 1 and 0) are irrational. This gives us radically different Riemann sums.

Consequently, we have to admit with a heavy sigh that it is impossible to integrate Equation (1) effectively.

3. On the other hand, there are times when we integrate stuff which aren’t functions. We won’t worry about what they are, or where they live, right now. Instead we will gleefully pretend everything is a function.

But an example of such an exotic creature. Well, the Dirac Delta “function”


About Alex Nelson

I like math. I like programming. Most of all, I love puzzles.
This entry was posted in Calculus, Integrable Functions, Integral. Bookmark the permalink.

2 Responses to Not all functions are (Riemann) integrable!

  1. Pingback: [Index] Calculus of a Single Variable | My Math Blog

  2. Pingback: [Index] Calculus in a Single Variable | My Math Blog

Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s